4x^2-18+3x^2-3x=180

Solution for 4x^2-18+3x^2-3x=180 equation:

4x^2-18+3x^2-3x=180

We move all terms to the left:

4x^2-18+3x^2-3x-(180)=0

We add all the numbers together, and all the variables

7x^2-3x-198=0

a = 7; b = -3; c = -198;
Δ = b2-4ac
Δ = -32-4·7·(-198)
Δ = 5553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5553}=\sqrt{9*617}=\sqrt{9}*\sqrt{617}=3\sqrt{617}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{617}}{2*7}=\frac{3-3\sqrt{617}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{617}}{2*7}=\frac{3+3\sqrt{617}}{14}
$